+\subsection{A sequence that seems to converge to a wrong limit - pgs 9-10, \cite{HFP}}
+
+\begin{align*}
+ u_n &= \left\{ \begin{array}{c} u_0 = 2 \\ u_1 = -4 \\ u_n = 111 - \frac{1130}{u_{n-1}} + \frac{3000}{u_{n-1}u_{n-2}}\end{array}\right.
+\end{align*}
+
+The limit of the series should be $6$ but when calculated with IEEE floats it is actually $100$
+The authors show that the limit is actually $100$ for different starting values, and the error in floating point arithmetic causes the series to go to that limit instead.
+
+\begin{figure}[H]
+ \centering
+ \includegraphics[width=0.8\textwidth]{figures/handbook1-1.pdf}
+ \caption{Output of Program 1.1 from \emph{Handbook of Floating-Point Arithmetic}\cite{HFP} for various IEEE types}
+ \label{HFP-1-1}
+\end{figure}
+
+\subsection{Mr Gullible and the Chaotic Bank Society pgs 10-11 \cite{HFP}}
+
+This is an example of a sequence involving $e$. Since $e$ cannot be represented exactly with FP, even though the sequence should go to $0$ for $a_0 = e - 1$, the representation of $a_0 \neq e - 1$ so the sequence goes to $\pm \infty$.
+
+To eliminate these types of problems we'd need an \emph{exact} representation of all real numbers.
+For \emph{any} FP representation, regardless of precision (a finite number of digits) there will be numbers that can't be represented exactly hence you could find a similar sequence that would explode.
+
+IE: The more precise the representation, the slower things go wrong, but they still go wrong, {\bf even with errorless operations}.
+
+
+\subsection{Rump's example pg 12 \cite {HFP}}
+
+This is an example where the calculation of a function $f(a,b)$ is not only totally wrong, it gives completely different results depending on the CPU. Despite the CPU conforming to IEEE.
+